Explain it

Question

int i;
i=1,2,3;
printf("i=%d",i);

Answer 1

Comma operator evalutes left hand operand and discards its result. Then it evaluates second operand and returns its value.

So result is 1. //not 3 , See next answer.

https://en.m.wikipedia.org/wiki/Comma_operator

Answer 2

Result is 1

Answer 3

Md Raziullah Khan ,
Can you try to understand second code by yourself?

I can answer , but in order to learn C you should be able to think about such things by yourself. It's not hard. At least try it once.

Try to answer second question. If you feel difficulty at any point you are welcome to ask.

Answer 4

Md Raziullah Khan ,
Thanks for pointing that out. 🤪

Here's explanation why is it so:

Comma operator has least precedence among all the operators available in C.

So i is assigned value 1 and then comma operator discards 1.

In order to evaluate rhs of expression before assignment we can use parantheses.

i = (1,2,3);
//now i will be 3

Answer 5

And
int a=14,b=12,c;
c=a>b?1,2,3:4,5,6;
printf("c=%d",c);

Answer 6

Answer is 3

Answer 7

It's just assignment operator has higher precedence than comma operator so that's just assigning i to 1.