Conditional Operator '?'

Question

let a = 10;
console.log(
(a < 5) ? "a is less than 5" :
(a = 5) ? "a is equal to 5" : "a is greater than 5"
);
//Why the output is not "a is equal to 5" but not "a is greater than 5"

Answer 1

AJ #Level 20 End Game No, output is "a is equal to 5"
Rest are correct, but single equal sign(=) assigned a's value to 5, where double equal sign(==) checks whether the operands' values are equal.
Copy that and check this in the playground

Answer 2

Look above example like this.

x = (a< 5) ? y : ((a = 5) ? z : w);

Here is 2 ternary operator so in first ternery operator a < 5 is false so output will be

(a = 5) ? z : w //here a = 5 false so output will be w

= w
= 'a is greater than 5'

Edited : here a = 5 not a == 5 so answer will be 'a is equal to 5'

Answer 3

Farhan Yes I got because here a = 5 not a == 5.

Thanks

Answer 4

The problem was the condition itself. Instead of '=' I was supposed to use '==' after which the code worked as intended.
Thanks for answering.