Make a square() function to multiply floats

Question

Hi guys, i want to modifie the code bellow in order to multiply a floats numbers:

But only the definition need be changed without having to make changes to the declaration.

#include <stdio.h>

void* square (const void* num);

int main() {
int x, sq_int;
x = 6;
sq_int = square(&x);
printf("%d squared is %d\n", x, sq_int);

return 0;
}

void* square (const void *num) {
int result;
result = (*(int *)num) * (*(int *)num);
return result;
}

Answer 1

You can't return something when the return type of a function is void .

Run this code for float values

#include <stdio.h>

float square (float *num);

int main() {
float x, sq_int;
x = 6.5;
printf("%f squared is :" , x);
sq_int = square(&x);
printf("%f\n",sq_int);

return 0;
}

float square (float *num) {
float result;
*num = (*num) * (*num);
result=(*num);

return(result);
}

Vote me if its helpful

Answer 2

Thanks for feedback, but I don't agree with you, Because the function pointer (void *) provides the possibility to return something.... Right!