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Python and JavaScript equivalent functions but different outputs

I simply rewrote the JS function in Python expecting the output to be the same but turned out different? Why? What should I do to the Python function so that it yields the same output as JS? https://code.sololearn.com/chRNdY58ItaQ/?ref=app https://code.sololearn.com/W3TYqwq93byp/?ref=app

27th Apr 2020, 3:18 AM
Fernando Moceces
Fernando Moceces - avatar
2 Respuestas
+ 2
Because default parameters are not handled the same way in Python and JS ^^ In JS, default argument values are assigned at runtime, while in Python, they are assign at function declaration time. So, when you do: def f(p,q=None): ... q will be the same list for each call, while in JS, q will be a new empty list at each call ;) You rather need to translate the JS behavior by doing: def f(p,q=None): q = q or []
27th Apr 2020, 6:05 AM
visph
visph - avatar
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Cleared! Thank you to both visph and Mirielle[Inactive] :)
27th Apr 2020, 8:52 AM
Fernando Moceces
Fernando Moceces - avatar