Access to an element array

Question

How can i access to an element that the user wants to access, example:

11 12 13
14 15 16
17 18 19

The useres input is 5

Then my program has to print the number 15

How can i do that?

Answer 1

I think for this you have to create new single dimensional array which stores this values as index no 0 1 2 ... 8.

Answer 2

https://code.sololearn.com/c7RBVO16W7lv/?ref=app
Pls why is the code not running efficiently. I want the user to enter the pin 1994 after which access will be granted to the usee

Answer 3

! Bad Coder but if the array is 3x4?

Answer 4

N * M = newArrayLength

Answer 5

Diego Becerril 2*2 = 4
You can only stored 4 values in it.

Answer 6

int[][] arr =
{
{ 11, 12, 13 },
{ 14, 15, 16 },
{ 17, 18, 19 },
{ 20, 21, 22 }
};

// User Input minus 1
var index = (5 - 1);

var x = index % arr[0].length;
var y = index / arr[0].length;

System.out.println(arr[y][x] + " / x: " + x + " / y: " + y);

Answer 7

For NxM matrix,
x=input/N;
y=input%M;
System.out.println(arr[x] [y]);

Answer 8

Dear Diego Becerril ,
Accessing elements in a double dimensional array or a multi-dimensional is quite simple.

Just ask the user to input the dimensions, I mean for example if you
have a 2-d array which has following elements.

11 12 13
14 15 16
17 18 19

Then user must enter 2 dimensions
I mean user must give 2 inputs
One input for first dimension which is row index here and other input for second dimension which is column index here.

Thus, if user enters

2 then
1

Then it accesses the element at row index 2 and column index 1

Therefore output will be 18

Remember indexing starts with 0.

Hope u understand!!!

Keep coding!!

Answer 9

the array is NxM

Answer 10

or there is no other way like puting the N value and the M value and searching it automaticly?

Answer 11

3 x 4 = 12
If array is 3x4 then you have to create array length of 12.

Answer 12

or the other way

11 12 13
14 15 16
17 18 19

number of row = 2
number of column = 2

the output is = 19

how can i do that, can you give me an example in code please?

Answer 13

Both multi-dimensional and single-dimensional array will do, the former being easier...
single dimensional will require you to do this while creating the array:
int i = (curRow*columns)+j;
arr[i] = ....;
where j is the less than columns and represent the current column, curRow represent the row you are currently working on.

you'd retrieve item 5 with no stress.
return arr[5];

Answer 14

I don't remember well java but it could work something like this.
Define array
Array=["..."]
Define variable input
X=value input
Define index
i= x;
Define variable element
Element=array[i]
>Print element
I guess that could work if is an 1d array. If not, should create variables to relate the value input with the index.

Answer 15

Send the code

Answer 16

They way you arranged the numbers it looks like a two-dimensional array.
The Indexes to access such an array would look like this:

[ 0,0 ] [ 0,1 ] [ 0,2 ]
[ 1,0 ] [ 1,1 ] [ 1,2 ]
[ 2,0 ] [ 2,1 ] [ 2,2 ]
To access for example "15" you have to take the index [ 1, 1 ], for "17" it would be [ 2,0 ].

Answer 17

the output where the user input is the row and the column and that numer has to be printed

Answer 18

thank you all guys i did it like this

//acutal array

/*11 12 13
14 15 16
17 18 19*/

int n,m;

sout(“column”);
n = s.nextInt(); //assuming n = 2
sout(“raw”); //assuming m = 2
m = s.nextInt();

sout(arr[n][m]);

output 19

Answer 19

the output where the user input is the row and the column and that numer has to be printed