Operator Precedence

Question

What is the answer for this:

What is the result of this code?
x = 4
y = 2
if not 1 + 1 == y or x == 4 and 7 == 8:
print("Yes")
elif x > y:
print("No")

i understand up to part 7==8.And then i don't understand what happen and what to do after print("Yes").I don't get it and what is the answer?

Answer 1

First of all we have three conditions :
1+1==y [y=2]
1+1==2
Hence this statement is True

x==4 [x=4]
4==4
This is also True

7==8
This is False

So our condition
not 1 + 1 == y or x == 4 and 7 == 8
is now
not True or True and False

Now according to operators precedence:
1.Arithmetic operators[already solved above]
2.not
3.and
4.or
Now evaluating it
not True or True and False
False or True and False
False or False
False

Hence if condition is false andelif is true because x>y

therefore answer will be No.

I Hope this helps🙂🙂

Answer 2

x = 4
y = 2

Let's break down the conditions :

1+1 == y # True. Because 1+1 = 2 and y is also 2. So 2 == 2 is True

However adding 'not' in front of True makes it false. So

not 1+1 == y # False

As it is false it moves forward and check the next condition. The next condition is :

x == 4 and 7 == 8

x == 4 is True but 7 == 8 is false. And know we know operator 'and' returns true only if all the condition is true. We can see that one condition is True and the second one is False. Therefore

x == 4 and 7 == 8 # False

And hence

not 1+1 == y or y == 4 and 7 == 8 # False

That is why 'Yes' doesn’t get printed. However we let's move forward.

x > y # True. Because 4 > 2

As a result we get 'No' as output.