How can I sort a "zip-list" after integer and not string?

Question

Hi! I used the zip function to merge three lists. One list consist of integers and the other two consist of strings. If I use sort now my "zip-list" is sorted alphabetical but I want it to be sorted after the integer in the list.

Example:

zip-list.sort()

My output:
[(a, e, 4),
(b, f, 1),
(c, g, 3),
(d, h, 2)]

But I want it to be:
[(b, f, 1),
(d, h, 2),
(c, g, 3),
(a, e, 4)]

I hope someone can help me. Thank you!

Answer 1

This can be done with a lambda and a custom key: ( sorting is done by index 2 = third element in tuple)

lst = [('a','f',3), ('k','c',1), ('l','f',0)]

res = sorted(lst,key=lambda x : x[2])
print(res)

# output = [('l', 'f', 0), ('k', 'c', 1), ('a', 'f', 3)]

Answer 2

must the list look exactly like the output you wanted? one way i can think if is put the int first of the 3 elements (1, b, f)- then zip-list.sort().
Then use for loop to rearrange the seqence of the tuple in the list again.
ie.
new_list= []
for a, b, c in zip_list:
new_list.append( (b, c, a) )