Why doesn't decorating work when you pass the input as an argument?

Question

The following prints the input without the decor:

def decor(func):
def wrap():
print("============")
func()
print("============")
return wrap

def print_text(x):
print(x)

decor(print_text("Hello World!"))

Answer 1

def decor(func):
def wrap(y):
print("============")
func(y)
print("============")
return wrap

def decor1(func):
def wrap1(z):
print("**************")
func(z)
print("**************")
return wrap1

@decor
@decor1
def print_text(x):
print(x)

print_text("hello, two decors")

Answer 2

But you have the text inside the function when defining it. How does one put it in as an argument:

print_text("Any text");

Answer 3

guga good job you kept the decor and the function and it works perfect. But could you do it without using @decor. Recreate what @decor does without using @?

Answer 4

Managed to get it without using @ by passing the text as a second argument:

def decor(func, x):
print("============")
func(x)
print("============")
return decor

def print_text(x):
return print(x)

decor(print_text, "Hello World!")

guga your solution is still better. Thank you.