How can we display floats in cpp without including <cstdio>? I tried by cout but it won't display decimal digits after "0".

Question

//used setprecision() for required digits
#include <iostream>

#include<iomanip>
using namespace std;

int main() {
int a;
long int b;
char c;
float d;
double e;
cin>>a>>b>>c>>d>>e;
cout<<setprecision(20)<<a<<endl<<b<<endl<<c<<endl<<d<<endl<<e;
return 0;
}
/* sample i/p:-
3
1354257897655556
a
334.2304
14049.304930000
*/

Answer 1

I think you can just type
fixed<<setprecision(20)

Answer 2

What do you mean?
Do you mean 2.7............?

Answer 3

YCS-Venom
Thanks for reply. Works fine upto 6 decimal digits.
"cout<<fixed<<a<<endl<<b<<endl<<c<<endl<<d<<endl<<e;" like this

Answer 4

How much do you want?

Answer 5

And do you want to fill it with zeros?

Answer 6

Only 6 digits were needed. But what if we want all digits for double e

Answer 7

YCS-Venom
I meant 14049.30493000

Answer 8

just type like this
double x=14049.30493000 ;
cout<<fixed<<setprecision(8)<<x;
Or you can type it directly

Answer 9

YCS-Venom
Yeah, I get that. But there are multiple test cases. I can't initialise any of them. Without using "setprecision ()" or "fixed" 5 out of 9 were wrong but I used fixed and it worked. So, thanks a lot.

Answer 10

Is it code couch?

Answer 11

YCS-Venom
No, it was some random question on hackerrank.

Answer 12

Can you give me the link?

Answer 13

YCS-Venom
It was one of the easy ones. Just trying without using printf
Link: http://hr.gs/4ljk3

Answer 14

Aditya Raj
That's work fine

int main() {
int a;
long int b;
char c;
float d;
double e;
cin>>a>>b>>c>>d>>e;
cout<<a<<endl<<b<<endl<<c<<endl<<fixed<<d<<endl<<e;
return 0;
}

Answer 15

YCS-Venom
Yeah, it works.

Answer 16

H+3=

Answer 17

You should use casting just like this:
Cout<<float(x+y);
As if one of the variables x, y or both of them is float , the result will be float. Even if the two variables were integers the result will either be float.