‘That’s Odd’ Python help

Question

#receive user input and store in list ‘nums’
nums = list(map(int, input().split()))

#store even numbers from nums
evens = [x for x in nums if x % 2 == 0]

#add together all the even numbers
print(sum(evens))

Could anyone PLEASE tell me why this wouldn’t be working?? I cannot for the life of me figure out what I’m doing wrong... as far as I can tell the only output I’m getting is “0”

Answer 1

num = int(input())
even = 0
value = 1

while value <=num:
value += 1
x = int(input())
if x % 2 == 0:
even += x

print(even)

Answer 2

Each number is input on a new line not all on the same line.

Answer 3

lenth = int(input())
a = 0
total = 0
while a<lenth:
i = int(input())
if i%2==0:
total+=i
a+=1
print(total)

for explanation dm me
no offense
i can explain better there...
cuzz comment box conversation is silly

Answer 4

ChaoticDawg so what parameter would i need to put inside split() for it to see ‘enter’ or ‘new line’ as the delimiter?

Answer 5

split takes all whitespace as delimiter.

However, the input function goes always until the next newline only.

So for this code, you have to enter all numbers in one line.

Answer 6

You need to loop to input N times

Answer 7

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
sum=sum+num;
print(sum)

}

""""

Answer 8

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
sum=sum+num;
print(sum)

}

""""

Answer 9

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
{
sum=sum+num;
print(sum)
}

}

""""

int sum = 0;
int i= 0;
while(num%2!=0)
{
sum=sum+num;
i=i+1;

print(sum);
}

""""

Answer 10

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
{
sum=sum+num;
print(sum)
}

}

""""

int sum = 0;
int i= 0;
while(num%2!=0)
{
sum=sum+num;
i=i+1;

print(sum);
}

""""

Answer 11

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
{
sum=sum+num;
print(sum)
}

}

""""

int sum = 0;
int i= 0;
while(num%2!=0)
{
sum=sum+num;
i=i+1;

print(sum);
}

""""

Answer 12

num=int(input())
sum=0

for i in range(num):
num=int(input())
if (num%2!=0):
sum=sum+num
print(sum)

""""
int sum = 0;
for(int i=0;i<=num;i++)
{
if(num%2!=0)
{
sum=sum+num;
print(sum)
}

}

""""

int sum = 0;
int i= 0;
while(num%2!=0)
{
sum=sum+num;
i=i+1;

print(sum);
}

""""

Answer 13

nums=[]
ans=0
range_of_nums=int(input())
while 1:
try:
nums.append(int(input()))
except EOFError:
break
for i in range(range_of_nums):
if nums[i]%2==0:
ans+=nums[i]
print(ans)

Answer 14

I thougnt something like that. On my console it is working.. but still not figure it out how to test it on app..

import random
number_list_all = random.sample(range(0, 10),10)
number_list_even = []
# 2 integer list'deki çift sayıları bulup yeni bir listeye gönder.
for even in number_list_all:
if even %2 == 0:
number_list_even.append(even)

print("the total even number are in the list: ", number_list_even)
print("all those number sum is :", sum(number_list_even))