What will be the output of the following C code?

Question

#include <stdio.h>

int *f();

int main()

{

int *p = f();

printf("%d\n", *p);

}

int *f()

{

int *j = (int*)malloc(sizeof(int));

*j = 10;

return j;

}

Answer 1

Sorry to say but there will not be any output as I found there is some error in your code. Just check your code again

Answer 2

All you have to do is just reading error reason:
As you can see it says malloc is declared in stdlib library and you fogot to include it

Answer 3

Just add "#include <stdlib.h>" without quotes below "#include <stdio.h>".
This is required to declare the prototype of malloc().

Now the output of the program will be 10: the content of the memory that you allocated and initialized inside the function f() 🤷