How to create a circle

Question

Can I create a circle using loop just like other patterns which are made in a similar way

Answer 1

def circle(r, p1, p2):
r = int(r)
if p1 == '':
p1 = '::'
if p2 == '':
p2 = '##'
side = r * 2 + 1
r1 = ( r - 0.5 ) ** 2
r2 = ( r + 0.5 ) ** 2
for row in range(side):
out = ''
for col in range(side):
d = ( col - r ) ** 2 + ( row - r ) ** 2
if r1 < d < r2:
out += p2
else:
out += p1
print(out)

r = input('Radius size of circle? ')

p1 = input('Pattern for empty text-pixel ( default "::" )? ')
p2 = input('Pattern for plain text-pixel ( default "##" )? ')

print()
circle(r,p1,p2)

Answer 2

Yeah... you can.
What I would doing for that goal, would be to set an two dimentional array representing a bit-map initialized with a default value, and set the cells crossing the perimeter of the circle with another ( using property of circle that all dot of circle are so distance from center to dot equals radius ). Next, I simply print my concatenated lines...

This should render a not perfect circle, as char aren't draw on a square pattern, but you can get near perfect by using monospaced font ( generally the case in console mode ) and two chars for a 'text-pixel' ( correct almost the deformation ). Else, you may improve your algorithm for drawing circle in your custom bit-map array by kept in account the pixel ratio ^^

Answer 3

If you don't want use a bit-map buffer, and do the trick just using loop and drawing line after line, you can also... You just may adapt the algoritm for drawing the 2 dots that cross circle with horizontal line: a 2D ray tracing ( known as rastering ), but you can also keep the radius algorithm...

Answer 4

https://code.sololearn.com/c8OeV7di4VTn/?ref=app