Module 2 quiz

Question

Fill in the blanks to print the first element of the list,if it contains even number of elements.

List = [ 1, 2, 3 , 4 ]
If___(list) % 2 == 0_
Print(list [ _ ])

Hello guys, please i need an explanation , so as to understand this question and the answer.

Answer 1

>>CORRECT CODE

List=[1,2,3,4]
if len(List)%2==0:
print(List[0])

>>There are error in your code

List = [ 1, 2, 3 , 4 ]
If___(list) % 2 == 0_

In line 2 error--

# "If" should be replaced by "if"
# "list" should be replaced by "List"

Print(list [ _ ])

In line 3 error--

# Indentation error.the print statement should be inside the if block.
#in place of "Print" it should be "print".
#"list" should be replaced by "List".

>>EXPLANATION

List=[1,2,3,4]
if len(List)%2==0:

#👆 here we have used "len" since in question you have asked if it has even length.so finding the length of list and then finding the remainder by taking "%".
If its equal to 0 means it's of even length and then it will print the first element of the list else the condition will be false.

print(List[0])

#print first element if of even length.

Answer 2

Thanks