Why do the else run after the first if run too?

Question

print("Hello, welcome to the temperature converter")
t=int(input("Which one you want to do? For F->C type 1, for C->F type 2"))
if t == 1:
f=float(input("What's the temperature?"))
c=5*(f-32)/9
print(c)
if t == 2:
c=float(input("Whats the temperature?"))
f=c*1.8+32
print(f)
else:
print("Invalid option")

As you can see there are 3 options on it, two "if" and one "else". But the problem that I dont understand is why when the first "if" in the top run then the "else" runs too.

Answer 1

having only two possible inputs check
if (input>2){
prompt for invalid option
}else{
if input==1
do something
else
do something else
}
in your code you do the input check twice for every input.
so when you type 1 the first if condition is met
(input ==1) and also the second else condition is met (input !=2)

if your input is 2 the first else condition is met (input!=1) and the second if condition is met (input==2).

Answer 2

Your else run coz of a second if. Change it to elif)
When you have 2 if'es in your code with else: one if your if'es can be triggered, but the second mb cant, so the esle block will come))

Answer 3

you might need an if-elif-else Statement instead of two if Statements. and the conditions may not be ambiguious

Answer 4

Ohh thanks guys. Since I'm still learning python I didnt know this "elif". I will search how to use it as well. This is one of my very first codes. And if you guys have any ideia how I could improve it that you want to share I would really appreciate it =)