[Solved]My approach on "Gapful numbers" problem.

Question

I am not sure whether.. my approach is good or not.

But any help will be appreciated.
Thank you

https://code.sololearn.com/c24sH0CNDKNk/?ref=app

Answer 1

Gapful Numbers: You can refer this codehttps://code.sololearn.com/cbmnK71jbl9f/?ref=app

Answer 2

try:
num=input()
assert (abs(int(num))>=100)

divisor=num[0]+num[-1]

if abs(int(num))%int(divisor )==0:
print(num,"is a gapful number")
else:
print(num,"is not a gapful number")

except(ValueError,AssertionError):
print("input must be integer atleast 3 digit long")

Answer 3

Sheikh Hafijul Ali
I saw SOLVED, but my code may help you

https://code.sololearn.com/cDrwI0cli1jp/?ref=app

Answer 4

Your approach is not good

Answer 5

suael Where is the problem.? is there any input that breaks my program?

Answer 6

Problem 1:Gapful numbers not need to be always 3 digit number for example 1001 and -1001 are gapful numbers.. so your assert should be assert(abs(int(num))>100)..

Answer 7

suael okay.. missed that part thank you.

Answer 8

i would say a good approach is to except value error and assertion error incase user enter a chaarcter string

Answer 9

suael have a look again on my code

Answer 10

Yes, indeed i should, but...

Answer 11

There is builtin abs function in python ..see above code ..

Answer 12

yes, there is.. but.. my code would require.. much more changes to use that way...

i would find it difficult to print the divisor in my code.. and finally the initial input...

Answer 13

this is not much change;.just make sure u make proper indentation for try and except