why isnt it working?

Question

this code is like "Siri". you have to write "siri" as the first word and a quwstuin mark at the end in order for it to work.
i added a thing if this combination of words are in the sentence it will give a random num between 1-100 ("how many").

why isnt it working when i write this combination of words?

code:

import re
import random

my_String = str(input("ask Siri a question:\n"))
my_String = my_String.lower()

popQ = my_String[-1:] #pop : peek
popS = re.findall(r'\w+', my_String) #the re.findall(what to filter , what string to filter from) function fillters all the punctuation marks and returns clean sentence!

randChoice = random.choice(["Yes" , "No" , "Sure" , "Maybe" , "Hell nah"])

if (popQ == '?' and popS[0] == "siri"):
if ("how many" in popS): #why isnt it working when i write 'how many'? (it should give me a random number between 0-100...)
print (random.randrange(100))
else:
print (randChoice)
elif (popQ != '?' and popS[0] == "siri"):
print ("Was that a question?")
elif (popQ == '?' and popS[0] != "siri"):
print ("Who are you asking?")

Answer 1

if "how many" in popS won't work because popS will be a list of single words. "how" may be immediately before "many" in the list popS, but "how many" in popS will still return False.

if "how many" in " ".join(popS) should work fine however.

Answer 2

the problem i found is the condition to check if "how many" was in popS.

seperated and checked for each word induvidually and it seems to work
https://code.sololearn.com/c9VPFBXucnsl/?ref=app

Answer 3

Thanks!