I want that the user will decide the value of x in the first line.

Question

x=int(input('enter values :'))
if x<=10 :
print ('''condition true''')
else :
print ('''invalid''')

Answer 1

https://code.sololearn.com/cnu2SFesTsRi/?ref=app

Answer 2

Ajay when you x= int(input()) you are changing x value
if you mean you can't change 10 then add y = int(input()) to change y

then
instead of if ( x <= 10 ): change to
if ( x <= y ):

Answer 3

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 I was in the heat of the moment 🤣🤣🤣 I am not usually profane. Sorry...

Answer 4

Tomiwa Joseph it is sometimes better to step away than bang your head ....

Answer 5

it is sometimes better to step away than bang your head ....

Wise words BroFar

Answer 6

Tomiwa Joseph words please...
Ajay is new here and may not understand anything at all yet.

Answer 7

Ok

Answer 8

1) you use ''' ......''' in your print(....). You have the choice only between "......" and '......'
2) actually your code does what you except but if you want the decision in a single line (I do not know if it is what you mean!) use: x=int(input('enter values :\n'))

Answer 9

Now code like that to have output . My output is error
But I want like that

Enter value :8
Condition true

Answer 10

Can I not change the value of x in kiibo ghayal code

Answer 11

I know very good when """...........""" are used in Python!
It is not pythonic to use them to print a single word!
I leave that Forum!!!

Answer 12

x=str(input('enter values :'))
x = list(x.split(','))
if len(x) <=10 :
print('''condition true''')
else:
print('''invalid''')

Did you mean this??

Answer 13

But how?, kiibo

Answer 14

Ajay
You have added comments b in print statement instead of using "'
Use " double quote or ' single quote

Answer 15

Read it