Incrementing an address

Question

int x = 10, y = 20;
int *ptr =&x;
int&ref = y;
ptr++;
ref++;
cout<< x << y; // outputs 1021

Out of curiosity, since ptr++ doesn't affect the final output, what actually happens to the memory location of x after we incremented ptr?

Answer 1

As i understand, nothing. Just ptr is now pointing on another memory location. They are different variables. You can check it by printing x address before and after incrementing

Answer 2

after ptr++, ptr will no more pointing to x. So x will not affect.
ref++ result same as y++, Since ref storing the refference to y, so both points to same location that is value 20.so ref++ make y=21.