What is the error in my code?

Question

https://www.sololearn.com/coach/55?ref=app

Answer 1

The task can be done in a rather simple way:

(1) take the input string and reverse it
(2) create an empty list for final result
(3) use a for loop to iterate over the input string
(4) in for loop check if character from input string isalpha() or if it is a space
(5) If yes: append this character to the final list
(6) use final list and ''.join() elements and print the result

Answer 2

How will we know the error without debugging and how will we debug when we don't have the code.

Show us your attempt.

Answer 3

ord(33) to ord(65) does not cover all the characters that must be skip.
Why don't you reverse the process instead of finding characters which shouldn't be in output, why not instead find the ones that are needed to be shown as output(the alphabets)
for example:
finding only the alphabets instead

REVERSING YOUR LOGIC:
message=str(input())
mes=list(message)
mes.reverse()

mes1=[]
for i in mes:
if (ord(i) >= 65 and ord(i) <= 90) or (ord(i) >= 97 and ord(i) <= 122) or ord(i)==32:
mes1.append(i)
print(''.join(mes1))

________________________________________
here's more improvement, why use list when we can achieve the same result using string

message=str(input())
mes=list(message)

mes1=""
for i in mes:
if (ord(i) >= 65 and ord(i) <= 90) or (ord(i) >= 97 and ord(i) <= 122) or ord(i)==32:
mes1+=i
print(mes1[::-1]) # "socat" is reversed here to our output - "tacos"

Answer 4

Jayndra Todawat , post your code linked to Playground so somebody can help you.

Answer 5

x=str(input())
a=[]
b="".join(filter(lambda x:x.isalpha(),x))
for i in x:
if i in b or i==" ":
a.append(i)
d="".join(a)
print(d[::-1])
this is what lothar said

Answer 6

Sorry guys
Rohit
TheWh¡teCat 🇧🇬
Blue_Ocean
Here is my code

n=0
message=str(input())
mes=list(message)
mes.reverse()
mes1=[]
for i in mes:
k=mes[n]
j=ord(k)
if j in range(33,65):
mes.remove(k)
else:
mes1.append(k)
n+=1
mes3=' '.join(mes1)
print(mes3)

Answer 7

Rohit
Thanx

Answer 8

Ayush Rastogi
Yes bro its worked
Thnx

Answer 9

Lothar
Yes I have done it in the manner u say..
Thnx for help

Answer 10

Jayndra Todawat
You forgot about space add this
if k==' ':
mes1.append(k)
And modify this
mes3=''. join(mes1) (no space)

Answer 11

v@msi😏😏
Thanks but It didn't work.
I think I must change my logic

Answer 12

s=input()
x=s[::-1]
st=""
for i in range(len(x)):
if x[i] in "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ":
st+=x[i]
print(st)
Try this.

Answer 13

Lol... 😂😂😂😂