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Why 7 / 2 = 3.0?
//I think it's a sololearn mistake double x = 7 / 2; System.out.println(x); //ouput 3.0 https://code.sololearn.com/c6uEc1cWs7VT/?ref=app
9 Respuestas
+ 7
//try running this...
public class Program
{
public static void main(String[] args) {
double x = 7.0 / 2;
// OR double x = 7 / 2.0;
// OR this double x = (double) 7 / 2; // Casting
System.out.print(x);
}
}
+ 7
it's not an error, it's just the way the compiler treats how operation should be done.
like in your case, we had
double x = 7/2;
okay x is double so we'll have our answer in Decimal points, fine!
But what about the values are they in double or int?
int, right?
so the compiler compiles this like
2 | 7 | 3
6
------------
1
only 3 is returned to x, however x is double so for the formality, the compiler keeps ".0" at the end of 3.
try making one of the values as double like so...
double x = 7.0 / 2;
or
double x = 7 / 2.0;
+ 5
7 and 2 are treated as integers.
change 7 to 7.0 or 2 to 2.0 to get a double division.
+ 2
Thanks!
+ 2
When you work with variables:
int a = 7, b = 2;
you would not be able to apply the previous tricks, then you would need to use type casting, if you want the result in doubles:
double x = (double) a / b;
//x = 3.5
+ 2
7and 3 is type of integer so you need type casting you will cast 7 to 7.0
and 3 to 3.0 it will return 3.5
+ 1
Oh thanks!
+ 1
The java compiler sees your 7 and 2 as integers and it only converts them to double types after they have been calculated as integers.
This means 7/2 will give 3.
And then the fact that you are assigning the answer to a double variable doesn't actually happen until the whole division.
Which means in
double x= 7/2
The value of x now is actually 3.0 and not 3.5 as you would have expected
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Thank you