I can't find my error, need help plss

Question

the problem is:
The university gives students discounts on tuition fees depending on their performance:
90-100 => 50%
80-89 => 30%
70-79 => 10%
0-69 => 0%
Write a program that will take the scores from the first and second semesters, then calculate the average score, and output the result, depending on the score.

Sample Input
67
83

Sample Output
10

this is my lines:

1 name = input()
2 sem1 = int(input())
3 sem2 = int(input())
4 #your code goes here
5 average = (sem1 + sem2) / 2
6 if average <= 69 and average >= 0:
7 print("0")
8 elif average <= 79 and average >= 70:
9 print("10")
10 elif average <= 89 and average >= 80:
11 print("30")
12 else:
13 print("50")''

and when I try to run it it tells me EOFerror line 3

Answer 1

End of file error, make sure you have the correct number of inputs and each one is on its own line.

Answer 2

score1 = int(input())
score2 = int(input())
ni = (score1 + score2) /2
if (ni >= 90 and ni <= 100):
print('50')
if (ni >= 80 and ni <= 89):
print('30')
if (ni >= 70 and ni <= 79):
print('10')
if (ni >= 0 and ni <= 69):
print('0')
try this one

Answer 3

score1 = int(input())
score2 = int(input())
ni = (score1 + score2) /2
if (ni >= 90 and ni <= 100):
print('50')
if (ni >= 80 and ni <= 89):
print('30')
if (ni >= 70 and ni <= 79):
print('10')
if (ni >= 0 and ni <= 69):
print('0')

Answer 4

score1 = int(input())
score2 = int(input())
average = ((score1 + score2) // 2)
if average >= 90:
print(50)
elif average >=80 and average<=89:
print(30)
elif average >=70 and average<=79:
print(10)
else:
print(0)

Answer 5

done, thanks for explanation man !

Answer 6

remove the first line from the code
name = input()
is an error
there only two input
and the first input is taken by the name = input()

Answer 7

score1 = int(input())
score2 = int(input())
avescore = (score1 + score2)/2
#your code goes here
if avescore >= 90 and avescore <= 100:
print(50)
elif avescore >= 80 and avescore <=89:
print(30)
elif avescore >= 70 and avescore <= 79:
print(10)
elif avescore >= 0 and avescore <=69:
print(0)

Answer 8

sem_1 = int (input("Enter semester 1 : "))
sem_2 = int (input("Enter semester 2: "))
avg = (sem_1 + sem_2) /2
#avg = num / 2
#print (avg)

if avg <= 100 and avg >=90:
print ("50% off")
elif avg <= 89 and avg >=80:
print ("30% off")
elif avg <= 79 and avg >= 70:
print ("10% off")
else:
print ("0% off")

Answer 9

sem1=int(input('Enter the semester 1 marks: '))
sem2=int(input('Enter the semester 2 marks: '))
avg=(sem1+sem2)/2
if(avg>=90 and avg<=100):
print('50')
elif(avg>=80 and avg<=89):
print('30')
elif(avg>=70and avg<=79):
print('10')
else:
print('0')

Answer 10

Below will work:

score1 = int(input())
score2 = int(input())
score3 = (score1 + score2) / 2
if(score3 >= 90 and score3 <= 100):
print('50')
if(score3 >= 80 and score3 <=89):
print('30')
if(score3 >= 70 and score3 <= 79):
print('10')
if(score3 >= 0 and score3 <= 69):
print('0')

My initial code:

#score1 = int(input())
#score2 = int(input())
#score3 = score1 + score2 / 2
#if(score3 >= 90 and score3 <= 100):
# print('50%')
# if(score3 >= 80 and score3 <=89):
# print('30%')
# if(score3 >= 70 and score3 <= 79):
# print('10%')
# if(score3 >= 0 and score3 <= 69):
# print('0%')

#NOTE:

# 1. I did not have the parenthesis to calculate the average.
# 2. My indentation was incorrect.
# 3. My output had percentages. For some reason percentages cause an error.
# Without the debugging of the above three points then I would not have successfully completed this practice.