Counting Numbers in a range

Question

# how can we modify this code to count the numbers in a given range which can divide by 2 we can’t use lists etc.

import math

while True:
num1 = int(input("input lower number: "))
num2 = int(input("input upper number: "))
for numbers in range(num1, num2 + 1):
if numbers % 2 == 0:
print(numbers)
else:
break

Answer 1

Well you don't need to import math and you don't need the while loop or the else block

Answer 2

can you use sets?

print({x for x in range(0,100) if x%2==0})

what about dictionaries?

print({i:x for i,x in enumerate(range(0,100),1) if x%2==0})

tuples?

print(tuple(x for x in range(0,100) if x%2==0))

Answer 3

there are other ways, yeah, but I don't think they will be as efficient as the ones we have already identified, the for loop does a pretty good job and the comprehensions do as well, the only other thing would be maybe a lambda or recursive function

Answer 4

You can use Pandas, but you are still storing your values in an array, you need to store the values somehow

import pandas as pd
x=int(input())
y=int(input())
z=range(x,y+1)
df=pd.Series(z,index=z).apply(lambda x: x%2==0)
print(df)
print(f"There are {sum(df)} in even numbers in {z}")

Answer 5

♤♢☞ 𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 ☜♢♤ This is what I’m looking for. thank you so much :)

Answer 6

print([1 for i in range(int(input()),int(input())+1) if i%2==0].count(1))

Answer 7

Kunevich Evgeniyy Evgenievich this is short and effective. thanks.

Answer 8

No we can’t use any of them. is there any other way?

Answer 9

so what should I do? for example if I give the first number 10 and second 20. then the numbers between this range is which can divide by 2 are:
10, 12, 14, 16, 18, 20

now I want another print that says “there are 6 even numbers”

how can I count these even numbers there?

Answer 10

♤♢☞ 𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 ☜♢♤ yes but I want to print how many even numbers between that range. for example if I entered 10 and 20 then it should give me the print that says “there are 6 even numbers”