Why does my code not work?

Question

I want it to create an object and automatically put its name into an array.
https://code.sololearn.com/wiwpL2ASz44Z/?ref=app

Answer 1

Michał Cukrowski within the constructor u can just add global keyword before the variable name:
global $array;
$array[] = $ha;

Answer 2

You are accessing the class property$array within the constructor, in php it is mandatory to access the class properties using $this reference..

And outside the class u r accessing $array directly without the the object

var keyword is deprecated from PHP v5.0
and public can be used alternatively or when not defined it is public by default

the property $a defined public within the class, please understand that it is not same as the variable outside the class, which u have used to create object.

Answer 3

https://code.sololearn.com/wY7DIed49Iy6/?ref=app

Answer 4

Thanks a lot!! I knew I was missing something very simple 😂

Answer 5

Hope that was helpful 😅

Answer 6

Sorry, I made a little typo here, I wanted $array to be outside the class as a global variable but being desperate I put it inside and mistakenly saved :)) I've already changed it, what should I do in such a situation?