Why does the countdown start on 3 when the print says i = i - 1 if i = 3?

Answer 1

Yes the countdown starts 3 because before the code i = i - 1 runs, "i" has already been set to 3. So after the code runs, then "i" will have new value of 2 and keep running down. But there is no condition to check when to stop, the syntax above isn't complete. It should be:

i = 3
while True:
if i > 0:
print(i)
i = i - 1
else:
break

Answer 2

I get that I just dont see the logic of printing i - 1 and the first number showing has not been substracted by - 1 when the code says print i, which in this case is 3, - 1 which would result in 2. As I was typing just now tho I realised that my view of how a loop works in python is wrong.

Answer 3

Yeah I guess, so print is done before subtraction, and after subtraction prints again before next subtraction until the condition is false and breaks out of loop.

Glad I could help....happy coding!