What the process going on to printing the value 1 . Not(not x or not y and x or not y)

Question

bool x= false;
bool y=true;
bool c =!(! x || !y && x || !y);
cout<<c;

Answer 1

Your code will give Output false (0)

bool x= false;
bool y=true;
Here !x means true and !y means false
bool c =!(! x || !y && x || !y);

bool c=!(true||false&&false||false)
bool c=!(true||false ||false)
c= true||false ||false
this will give result but there is not before bracket so true will be false
cout<<c;