Python: How should we interpret 'lambda x:not any(p in x for p in ['#x27;,'%'])'?

Question

def fs(lst,fil):
zzz = lambda x:not any(p in x for p in fil) # How should we interpret this?
return list(filter(zzz,lst))

lst=['$aaa','@bbb','%ccc']
f=['

Answer 1

There x is assigned a value each time from iterable lst.
So there p in x works like
$ in $aaa true, next $ in @bbb false, $ in %ccc false,
next
% in $aaa is false , % in @bbb is false, % in %ccc is true
So not any is needed all false so return @bbb
For just
any(p in x for p in fil) returns $aaa, %ccc

Iterables are worked by taking each value at a time into temporary variable. Just like almost similar to for loop.....