Why the array starts from 0 ?

Question

please i am tired but not found any satusfied answer.
help out me. !!

Answer 1

I guess because arr[i] means *(arr + sizeof(type) * index). So if you want to address the first element, i should be 0). Sorry if my notation is wrong or not understandable.

Answer 2

It's because it's technically an offset in an array, due to the use of a pointer in the program to call on indices. So the nth index is '0' away from itself, and the 2nd index is 1 away, and so on. Think of it less as a number, and more as an offset(or relationship) from the start(the zeroth position).

Answer 3

That's just a rule like why 1=1... it needs to define rules to build something. Just take it like that, don't think about.

Answer 4

but there's a logic behind it .
i want that . :)