Why doesn't this translation work? (Brainfart to C)

Question

Hello.

I wanted to make a compiler for brainfart, which simply converts brainfart's symbols to the equivalent C statements, like in the map from Brainfart's Wikipedia page:
brainfart command C equivalent
(Program Start) char ptr[30000] = {0};
> ++ptr;
< --ptr;
+ ++*ptr;
- --*ptr;
. putchar(*ptr);
, *ptr=getchar();
[ while (*ptr) {
] }

I tried with ++++++++[>++++++++<-]>+. which is supposed to print character A,
but the C program equivalent runs in errors, which will seem to be weighted on ++ptr; and --ptr; statements.

Why do the errors appear?

C-equivalent:
https://code.sololearn.com/cH7AJF3KGzSX/#c

Answer 1

Seb TheS

char* p = ptr;

Then do all of the things with p.

Answer 2

Array can convert to a pointer, BUT it itself "is not" a pointer. It's a container.

++ and -- cannot be applied to an array. You need to declare a pointer which points to the array.

Also putchar() typo.

Answer 3

CarrieForle Viceversa is better:
char p[30000] = {0};
char* ptr = p;

The problems seem to be fixed now, thanks a lot!

Answer 4

@CarrieForle Typos are fixed, but I don't know what to do. Should I declare the array differently?