does arrangement matter in this?

Question

hello, why does this code output something which is "yo yo yo"

#include <iostream>
#include <string>
using namespace std;

class myClass
{
private:
string name;
public:
void setName(string x)
{
name=x;
}
string getName()
{
return name;
}
};

int main()
{
myClass obj;
obj.setName("yo yo yo");
cout << obj.getName();
}

and by changing name=x; to x=name;
it doesn't output anything???

Answer 1

Definitely Matters.
In name = x ; here x value assigned to name. It works like : target = source; source => target.
In first one, you are passing string into x and assigning to name. Now x, name have values =>"yo yo yo".
In next x = name, name is still unassigned no value, and getting assigned to x. And printing name, now see both x, name have none values.

Answer 2

obj.setName sets the value of name variable to yo yo yo and getName() returns it

name=x means assign x value which is yo yo yo to variable name

x=name means assign variable name which is unintialized to variable x which is being passed the yo yo as output ,anyway that's totally valid ,the reason you aren't getting output is because you are returning name variable not x