+ 3
Increment Question
<?php $x = 2; $y = $x++; echo $y; ?> Why the result is 2. x = 2, and when x ++ that Means should be 2 + 1. And the result is 3. But why 2?
6 Respuestas
+ 2
$y = $x++;
is equal to
$y = $x;
$x = $x + 1;
$y = ++$x;
is equal to
$x = $x + 1;
$y = $x;
+ 2
there is a lot of diff between x++ and ++x .
x++ means post incrementation, hence value of x++ remains same as that of x,and x is incremented later on.
+ 1
$y = $x++;
set current value of $x (2) to $y then increment $x to 3
obtain 3 with $y = ++$x;
+ 1
yes
+ 1
$y = $x++ means that you assign the value of $x (2) to $y and THEN you increase the $x value from 2 to 3. That's why echo $y is 2, not 3.
0
so, if i answer 3, this is value of $x?