Need help with daysinmonth() function: my 'else' for def daysinmonth(x, y) is not working it should give out '31' as answer

Question

def isleap(y):
if y % 400 == 0:
return True
elif y % 100 == 0:
return False
elif y % 4 == 0:
return True
else:
return False
# x is month and y is year
def daysinmonth(x, y):
if x == 2:
isleap (y)
if isleap(y) == True:
return 29
else:
return 28
elif (x == 9, 4, 6, 11):
return 30
else:
return 31
print (daysinmonth(3,2020 ))

# my 'else' for def daysinmonth(x, y) is not working it should give out '31' as answer instead it gives '30'; so maybe theres problem with elif or else

Answer 1

The way you have done the else condition does not work as expexted. when having x = 3, the expression x == 9,4,6,11 gives:

(False, 4, 6, 11) This is a tuple.

better use in operator:

elif x in [9, 4, 6, 11]: # you can omit the parenthesis !

this will return 31.