functon

Question

def minimum(x,y):
x=int(input("enter the first number"))
print(x)
y=int(input("enter the second number"))
print(y)
if x>y:
return y
else:
return x

minimum( , )#i don't know what should i put here
#this code ask for two numbers then will show the minimum but as you see doesnt work correctly.can you help me.

Answer 1

If you are going to collect the inputs in the function, you don't need parameters in function header. you can do it like this:

def minimum():
x=int(input("enter the first number"))
print(x)
y=int(input("enter the second number"))
print(y)
if x>y:
return y
else:
return x

print(minimum())

Answer 2

You have a general problem with parameters and input through some of your codes as far as I could see.

Functions are
1. defined
2. Called

Up to now u did the Definition.
Here please only work with parameters x and y...not with input

Now for call:
a=int(input())
b=int(input())
#here comes the call
print(minimum(a,b))

Answer 3

def minimum(x,y):

if x>y:
return y
else:
return x

x=int(input("enter the first number"))
print(x)
y=int(input("enter the second number"))
print(y)
print(minimum(x,y))