Find the number of even numbers that are in range between the maximum and minimum elements of an given array

Question

Input:
First line contains n (1<=n<=100)
Than n numbers are inputed.
Output:
The number of elements between minimum and maximum.
Samples:
Input Output
8 2
-1 2 2 1 9 2 4 0

https://code.sololearn.com/c9vyQAQ9CIVM/#cpp

Answer 1

Rather than saving <min> and <max>, find index of <min> and index of <max> instead. You can then iterate the array from index of <min> to index of <max>, counting even numbers as you go.

You may be able to locate the index of <min> and <max> by using just one for-loop 👍

Answer 2

#include <iostream>
using namespace std;
int main(){
int a;
cin>>a;
int b[a];
for(int i=0; i<a; i++){
cin>>b[i];
}
int min=b[0];
int max=b[0];
int index_min=0;
int index_max=0;
for(int i=0; i<a; i++){
if(b[i]<min){
min=b[i];
}
if(b[i]>max){
max=b[i];
}
}
for(int i=0; i<a; i++){
if(min==b[i]){
index_min=i;
break;
}
}
for(int i=0; i<a; i++){
if(max==b[i]){
index_max=i;
break;
}
}
if(index_min > index_max)swap(index_min, index_max);
int o = 0;
for(int i=index_min+1 ; i<=index_max; i++){
if(b[i]%2 == 0){
o++;
}
}
int *s=&o;
cout<<*s;
return 0;
}