What’s wrong with this JavaScript code

Question

It’s a practice question in sololearn javascript. Practice Using “return”. Question and my coding (After //complete the function) as follows and I am not sure what’s wrong with it.

Question:
You are given a program that takes 3 numbers as input.
Complete the given function to calculate the average of those 3 numbers, assign it to the given variable, and output it.

Sample Input
3
6
9

Sample Output
6
............................................................

Coding:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/2;
return average;}

console.log(avg(num1,num2,num3));

Answer 1

updated (thanks it works now) really appreciate it :

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);
console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/3;
return average};

Answer 2

function main() {
var num1 = parseInt(readLine(), 10);
var num2 = parseInt(readLine(), 10);
var num3 = parseInt(readLine(), 10);

var average;

//assign the average value to the variable average

average = avg(num1, num2, num3);
console.log(average)

}

//complete the function
function avg(...args) {
let result = args.reduce((acc, current) =>
acc + current);
return result / args.length;
};

This function is more common.

Answer 3

the working solution...

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);

console.log(average);

}

//complete the function
function avg(num1,num2,num3){
return (num1+num2+num3)/3;
}

Answer 4

hi, you must divide with number of numbers.
in this case is 3.

Answer 5

i tried changing to the following:

function avg(num1,num2,num3){
var average = (num1+num2+num3)/3;
return average;}

console.log(avg(num1,num2,num3));

the output says “num1 is not defined”

i am confused as num1 is clearly defined.

Answer 6

Cheri Yan num1 is defined inside function main() ,
Call avg(num1,...) function inside that main to access num1 ,num2 and num3 variable

Answer 7

Where you adding console.log () statement?

Try this..
Cheri Yan
IN main function :

..
var average = avg(num1, num2, num3) ;
console.log(average)
}

Answer 8

if i put var average in the main , as suggested. it becomes:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);
console.log(average)

}

//complete the function

the output is: reference error again saying “avg” is not defined.

Answer 9

It works without the second function and no return needed :)

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average = (num1 + num2 + num3) / 3;

//assign the average value to the variable average

console.log(average)
}

Answer 10

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average
average = (num1 + num2 + num3) / 3
console.log(average)

}

//complete the function
function avg(){

}

Answer 11

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3)/3;

return average

}

//complete the function
function avg(num1 ,num2 ,num3){

console.log((num1 + num2 + num3)/3)

Answer 12

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);

console.log(average)

}

//complete the function
function avg(num1,num2,num3){
var average = (num1 + num2 + num3)/3;
return average;
}

Answer 13

updated (thanks it works now) really appreciate it :

function main() {
var num1 =updated (thanks it works now) really appreciate it :

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);
console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/3;
return average}; parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

average = avg(num1,num2,num3);
console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/3;
return average};

Answer 14

The given code takes 3 numbers as input.
Complete the program to output the maximum of the 3 inputs.

Answer 15

What’s wrong with this JavaScript code

It’s a practice question in sololearn javascript. Practice Using “return”. Question and my coding (After //complete the function) as follows and I am not sure what’s wrong with it.

Question:
You are given a program that takes 3 numbers as input.
Complete the given function to calculate the average of those 3 numbers, assign it to the given variable, and output it.

Sample Input
3
6
9

Sample Output
6
............................................................

Coding:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/2;
return average;}

console.log(avg(num1,num2,num3));

Answer 16

https://www.sololearn.com/Discuss/2565125/?ref=app

Answer 17

What’s wrong with this JavaScript code

It’s a practice question in sololearn javascript. Practice Using “return”. Question and my coding (After //complete the function) as follows and I am not sure what’s wrong with it.

Question:
You are given a program that takes 3 numbers as input.
Complete the given function to calculate the average of those 3 numbers, assign it to the given variable, and output it.

Sample Input
3
6
9

Sample Output
6
............................................................

Coding:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/2;
return average;}

console.log(avg(num1,num2,num3));

Answer 18

What’s wrong with this JavaScript code
What’s wrong with this JavaScript code

It’s a practice question in solole
It’s a practice question in sololearn javascript. Practice Using “return”. Question and my coding (After //complete the function) as follows and I am not sure what’s wrong with it.

Question:
You are given a program that takes 3 numbers as input.
Complete the given function to calculate the average of those 3 numbers, assign it to the given variable, and output it.

Sample Input
3
6
9

Sample Output
6
............................................................

Coding:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/2;
return average;}

console.log(avg(num1,num2,num3));

Answer 19

What’s wrong with this JavaScript code

It’s a practice question in sololearn javascript. Practice Using “return”. Question and my coding (After //complete the function) as follows and I am not sure what’s wrong with it.

Question:
You are given a program that takes 3 numbers as input.
Complete the given function to calculate the average of those 3 numbers, assign it to the given variable, and output it.

Sample Input
3
6
9

Sample Output
6
............................................................

Coding:

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

console.log(average)

}

//complete the function
function avg(num1 ,num2 ,num3){
var average = (num1 + num2 + num3)/2;
return average;}

console.log(avg(num1,num2,num3));

Answer 20

The given code takes 3 numbers as input.
Complete the program to output the maximum of the 3 inputs.