[Answered] Average Word Length problem

Question

I have tried multiple times to solve this question. I've also viewed the other posts on this, but nothin worked out for me. Here is my code:

string_to_calc = input()
string_to_calc = ''.join(filter(lambda x: x not in '",;!?-', string_to_calc))
len_of_each_word = [len(word) for word in string_to_calc.split()]

average_word_len = sum(len_of_each_word) / len(len_of_each_word)

if average_word_len % 1 >= 0.5:
average_word_len = int(average_word_len + 1)

else:
average_word_len = int(average_word_len)

print(average_word_len)

Answer 1

Harsh Kothari , just use the ceil function, you don't need the if-else part. Don't forget to import math module first.

Answer 2

Harsh Kothari , in fact not the same. The if part will be always false because modulus division to 1 will give always 0 and 0 >= 0.5 is false.

Answer 3

from math import ceil as ce
phrase = "".join(c for c in input() if c.isalpha() or c == " ")
words = phrase.split()
print(ce(sum(len(word) for word in words) / len(words)))

Answer 4

TheWh¡teCat 🇧🇬 That worked, but I don't know the reason why it did, cause didn't I do the same thing?

Answer 5

TheWh¡teCat 🇧🇬 Thank you

Answer 6

TheWh¡teCat 🇧🇬 so it wont give the decimal places?