Create a timer program that will take the number of seconds as input, output the remaining time and countdown to 0.

Question

Hey guys I'm beginner here and don't know how to do this every time I tried I got so many numbers in negative part. Can someone please help me.

Answer 1

I think this is something what you're looking for!

https://code.sololearn.com/cUWS8NP8FWTD/?ref=app

Answer 2

package main
import "fmt"
func ( x *Timer ) tick(){
x.id++
fmt.Println(x.id)

}
type Timer struct {
value string
id int
}

func main() {
var x int
fmt.Scanln(&x)

t := Timer{"timer1", 0}

for i:=0;i<x;i++ {
t.tick()

}
}

Answer 3

C++/C Challenger✔️✅☑️

Thank you so much sir for your help ☺️☺️

Answer 4

Look in the beginning of the course to learn about 'input' and 'loops'

Answer 5

# take the number as input
number = int(input())

#use a while loop for the countdown
while number >=0:print(number);number = number - 1

Answer 6

You can either use a for loop or add a second condition to stop seconds below 0

Answer 7

create code on your language and link on your code, better remove this topic and create new topic with code , question and link on your code. In code will write comment “what do you want to do”example: input and output

Answer 8

#include <iostream>

using namespace std;

int main()
{
int seconds;
cin >> seconds;

while (seconds >= 0){

cout <<"timer : "<<seconds<<endl;

seconds=seconds -1;
}

return 0;
}

Answer 9

Nasif Rahman
#include <iostream>
using namespace std;

int main()
{
int seconds = 3 ;

while (seconds < 4){
cout << seconds << endl ;
seconds = seconds - 1;
}
return 0;
}

Answer 10

Olivia I tried but i got nothing There's nothing about it

Answer 11

Ticking Timer

You are building a Timer app that should count up to a given number.
Your program needs to take a number as input and make the Timer tick that number of times.

The code in main initializes a Timer and takes a number as input. Then it calls the tick() method for the Timer the given number of times.

Define the Timer struct with two fields: id and value, and define the tick() method, which should increment the value by one and output its current value.

package main
import "fmt"

func main() {
var x int
fmt.Scanln(&x)

t := Timer{"timer1", 0}

for i:=0;i<x;i++ {
t.tick()
}
}

can anyone answer it in golang please

Answer 12

#include <iostream>
using namespace std;

int main()
{
int seconds;
cin>>seconds;

//your code goes here
while (seconds >= 0) {
cout << seconds << endl;
seconds--;
}

return 0;
}

Answer 13

// thank me later
#include <iostream>
using namespace std;

int main()
{
int seconds;
cin >> seconds;

while (0 <= seconds){
cout << seconds << endl;
seconds--;
}
return 0;
}

Answer 14

At python
--------------------
# take the number as input

number = int(input())

#use a while loop for the countdown

while number >= 0:
print(number)
number -= 1

Answer 15

Olivia some examples please

Answer 16

#include <iostream>
using namespace std;

int main()
{
int seconds;
cin>>seconds;

//your code goes here
cout << seconds << endl;
while (seconds > 0){
seconds --;
cout << seconds << endl;
}

return 0;
}

Answer 17

let num = parseInt(readLine(), 10);

//your code goes here
while (num > -1) {
console.log(num);
num--;
}

using javascript

Answer 18

number =int(input())
while number>=0:
print(number)
number=number-1

Answer 19

# take the number as input
number = int(input())

#use a while loop for the countdown
while number in reversed(range(4)):
print(number)
number = number - 1

while number in reversed(range(6)):
print(number)
number = number - 1

Answer 20

# take the number as input
number = int(input())

#use a while loop for the countdown