To check whether the number is palindrome or not and return y or n accordingly

Answer 1

hint:
*no need to convert str
*what is palindrome? hm?
*forward backward... got it?

Answer 2

Many of this community CAN solve this O-N-E...
But they don't want.
there is difference between want and cant
We can but dont want
You want but cant
Cabish?

Answer 3

Homework? Where is your attempt?

Answer 4

num = int(input("Enter a number: "))
def palindrome(num):

temp = n
rev = 0
while (n > 0):
digit = n % 10
rev= rev*10+dig
n=n//10

if (temp==rev):
return "yes"
else:
return "no"

print(num,"\nis an palindrome number ")
print(palindrome(num))

Answer 5

I have tried but this is not working

Answer 6

Even i am confused in this pls let me know if anyone can solve this one..

Answer 7

Oh ohk thats so sad😞😞

Answer 8

num = int(input("Enter a number: "))
def palindrome(n):

temp = n
rev = 0
while (n > 0):
digit = n % 10
rev= rev*10+dig
n=n//10

if (temp==rev):
return "yes"
else:
return "no"

print(num,"\nis an palindrome number ")
print(palindrome(num))

#You need to understand code each part first..

Answer 9

Do a little modify to satisfy your need.

https://code.sololearn.com/c18Ltdc8It25/?ref=app