Has anyone solved "if case #5" about ice cream for 10 friends in python course?

Question

Can't carry out the 4th hidden case

Answer 1

Алексей Тимаков their might be some wording problem which added some confusion. As of your code if you update it with changing last if statement to only
money = int(input())
price = int(input())

total = price*10
#your code goes here
if money >=0 and price>=0:
remaind = money - total
if remaind<=100 and remaind>=0:
print (remaind)
Than the problem should be fixed.

Answer 2

Алексей Тимаков
I'm not a pro user. Can you state the problem?

Answer 3

money = int(input())
price = int(input())

total = price*10
#your code goes here
if money >=0 and price>=0:
remaind = money - total
if total <=100 and remaind >=0:
print (remaind)

Answer 4

BeegCat , thanks a lot!

Answer 5

I've tried so many times and so many variants but it still doesn't work. Red a lot of threads about this issue, but the problem hasn't gone

Answer 6

Let's imagine you want to buy an ice-cream for 10 of your friends.
Write a program that will take the money you have and the price of one ice-cream, and will output the remaining money only if you can buy that ice-cream for your all 10 friends.

Sample Input
80
7

Sample Output
10

Explanation
To buy 10 ice-creams you need 7*10 = 70.
The remaining money is 80-70 = 10.

And don't output anything if total price is over 100.
That's the whole task.

Answer 7

Gawen Steasy, I've tried as you offered me and it works! But I think there's a mistake in the text of the task (about not to output anything if total price is over 100).
P.s. how to answer to someone in this chat - can't find this function...