sizeof operator using pointers

Question

#include<stdio.h>
#include<string.h>
int main()
{
char a[]="Access\0";
char b[]="Access";
char *p="Access\0";
char *q="Access";

if(p==q)
{
printf("\n");
printf("Access 1");
}

if(sizeof(a)==sizeof(b))
{
printf("\nAccess 2");
}

if(sizeof(p)==sizeof(q))
{
printf("\nAccess 3");
}

if(strlen(a)==strlen(b))
{
printf("\nAccess 4");
}

if(strlen(p)==strlen(q))
{
printf("\nAccess 5");
}

return 0;
}

Answer 1

U should try yourself in playground

Answer 2

Anyone gave the output of this code ??

Answer 3

And how this code work ??