Why is this program taking 6 input instead of 5.

Question

#include<stdio.h>

int sum (int,int,int,int,int);
int average(int);
//float deviation(float);

int main()
{
int a,b,c,d,e,p,q;
printf("enter the 5 number\n");
scanf("%d%d%d%d%d\n",&a,&b,&c,&d,&e);
p=sum(a,b,c,d,e);
printf(" sum=%d",p);
q=average(p);
printf(" avg=%d",q);

return 0;
}
int sum (int x,int y,int z,int m,int n)
{

int s;
s=x+y+z+m+n;
return (s);
}
int average (int r)
{

int t;
t=r/5;
return (t);
}

Answer 1

Remove \n from scanf format specifier, and also put spaces in between %d ...

scanf("%d %d %d %d %d" ,&a, &b, &c, &d, &e);

Use \n for inserting line breaks when printing outputs (using printf()). Not when reading input (using scanf()).

Answer 2

Ravi anshuman Hello,you code working properly,take only 5 numbers as input...

https://code.sololearn.com/cM7r2F3LzR6O/?ref=app

Answer 3

Ipang but his code working properly..
Ravi anshuman no errors in your code it works properly, just give 5 number in input

Answer 4

This program is only taking 5 inputs..

Answer 5

In Code Playground yes,
But not when I test ran it in CDroid
Test it in offline compiler bro ...

Answer 6

@ipan thanks.....that was a terrible mistake.

Answer 7

No problem Ravi we're all humans bro 👌