Number of digits after dot in c++ using printf

Question

In this code , i can print MY NUMBER with 2 numbers of digits after decimal point .

MY NUMBER is 1.72627827...

Code :

printf( "%0.2f" , 1.72627827);

...........

Now I want print MY NUMBER with N numbers of digits after decimal point .

N is giveen by user with cin .

How can i do that ?

Answer 1

int N;
cin >> N;
printf("%.*f", N, 1.72627827);

Answer 2

Thanks ... it works !

But what does it mean ?

"%.*f"

Answer 3

http://www.cplusplus.com/reference/cstdio/printf/

All about printf you need to know!