Write a program to accept any number and display the sum of digit of this number in c++? Where is error in this code?

Question

#include <iostream>
using namespace std;
main()
{
int num ,d,sum=0;
cout <<"Enter any number "<<endl;
cin>>num;

while(num!=0)
{
d, num % 10;
sum=sum+d;
num=num/10;
}
cout<< "enter any digit ="<<sum;

return 0;
}

Answer 1

//Check this code...
#include <iostream>
using namespace std;
int main()
{
int num,sum=0;
cout <<"Enter any number "<<endl;
cin>>num;

while(num!=0)
{
int d = num%10;
sum=sum+d;
num=num/10;
}
cout<< "enter any digit ="<<sum;

return 0;
}

Answer 2

#include <iostream>
using namespace std;
main()
{
int num ,d,sum=0;
cout <<"Enter any number "<<endl;
cin>>num;

while(num!=0)
{
d, num % 10;
sum=sum+d;
num=num/10;
}
cout<< "enter any digit ="<<sum;

return 0;
}

Answer 3

Harsh Kumar

Try to attach your code in description rather then posting it as an answer..

It will make more chances of getting answers!

Answer 4

Thanks Ujjawal sharma

Answer 5

https://code.sololearn.com/ccg3RRTMGlwo/?ref=app Harsh Kumar yours worked you just needed an equals operater “=“ between d and num%10.

Answer 6

so id loop from 1 to the number entered and add each iteration to a sum variable ( sum += number ) then just print sum to the screen outside of the loop

Answer 7

Where is error in this code?

Answer 8

Harsh Kumar I misread, you want the sum of the literal digits in the number.