I'm having problems with "int" in java

Question

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
int a=0;
for(int x = 0;x<6;x++)
{
a = (amount/10);

amount = amount-a;
}
System.out.println(amount);
}
}

Above code is answer of java program in this app (loops section).
In test case 100000 answer should be 53144 but my answer is coming 53145.
I have figured out that problem lies at "a= amount/10".
Here in last loop a value is coming 4.9 at ones place but code is converting it to 4 resulting my answer wrong. I tried ceil function, round off, making a double then converting it further to int but nothing worked... Please help

Answer 1

Vishal Sharma

Take input as double

Scanner scanner = new Scanner(System.in);
double amount = scanner.nextDouble();
//your code goes here
int i = 0;

while (i < 6) {
amount = amount - Math.ceil(amount * 0.1);
i++;
}

System.out.print((int) (amount));

Answer 2

Vishal Sharma , use Math.ceil method. According to your code => a = Math.ceil (amount * 0.1).

Answer 3

Vishal Sharma

Use Math.ceil like

amount = amount - Math.ceil(a)

System.out.println((int) amount);

Answer 4

I Am Groot ! Ya bro I already solved with this method but solo learn already mentioned amount as Int so I was thinking if anything can happen within those limits... Otherwise this is correct

Answer 5

TheWh¡teCat 🇧🇬 I Am Groot ! I already tried to use that but error is occurring "possible lossy conversation from double to int" in this line having ceil function

Answer 6

Vishal Sharma

Declare a with double.

Answer 7

for(int i = 0; i < 6; i++){

amount -= (amount * 0.10);

}
System.out.println(amount);

Answer 8

I Am Groot ! When I'm declaring a as double then same problem is occurring as amount is int and we can subtract double from int also we can't change amount to double coz it is specially mentioned in question