Rotate an array

Question

To rotate by one, store arr[0] in a temporary variable temp, move arr[1] to arr[0], arr[2] to arr[1] …and finally temp to arr[n-1]
Let us take the same example arr[] = [1, 2, 3, 4, 5, 6, 7], d = 2
Rotate arr[] by one 2 times
We get [2, 3, 4, 5, 6, 7, 1] after first rotation and [ 3, 4, 5, 6, 7, 1, 2] after second rotation

Answer 1

《 Nicko 12 》 your code is right .....
Thanks

Answer 2

lst = [1,2,3,4,5]

for i in range(2):
lst.append(lst.pop(0))

print(lst)

Answer 3

《 Nicko 12 》try it for [12,34,98,33]

Answer 4

Prateek Kalwar Its working just fine but can you tell me whats the problem? Because I know that the code could be wrong cause its too simple, I just want to know what is wrong, for myself. Thanks!

Answer 5

Mirielle[ INACTIVE ] Oh yes, Youre right, now I noticed even though its correct it is not actually a rotation, It just return the 1st value then append it to the list(which is not a rotation).

Thank you for letting me know!😊 That will help me in future codes.

Answer 6

https://code.sololearn.com/c1A10A17A6a2/?ref=app