How to create a prog. that will continuously accept a number and stops only if the last input number is twice the previous no.?

Question

Give me an example and I'll review it thank you in advance:)

Answer 1

Joyce , you just have started with the c# tutorial. so maybe you should continue reading the tutorial if you missed loops. otherwise go back some steps in the tutorial, read it again and do some practice too.

Answer 2

Just use a do while loop and an variable prev which stores the previous input. Then take input and store it in another variable cur.
In condition of while loop check if cur != 2*prev. When cur is twice this condition becomes false and the while loop will stop.

I don't know the exact syntax of c# but here's a general solution:

int prev, cur=maxint;
do
{
prev=cur;
cin>>cur; //Take input
}while(cur!=2*prev);

Answer 3

Joyce As Lothar said, maybe because its too early for you to understand, just keep learning and get more familiar with if else and loops and their working, then it'll be easier for you to understand.

Answer 4

I didn't get it, sorry I'm slow learner sorry 😩☹️ but thank you appreciated your explanations. ❤❤

Answer 5

Static void main()
{
int x=0,y=0;
while(true)
{
if(x!=2y)
{
int x=int.Parse(Console.ReadLine());
int y=x;
}
else
Break;
}
}