How to convert decimal into binary using lambdas ?

Question

I am trying to print the binary values of decimal numbers by using python inbulit lambdas

input : 32

output : 0010 0000

My attempt :

https://code.sololearn.com/c4vqA840S8Da/?ref=app

Answer 1

Jan Markus , your solution is unbeatable short and clear. here is an solution with bin() function:

for integer 5 it will give:

0b101

so it contains a prefix "0b" that this number is a binary number. when converting these kind of numbers back to integer, it can be done with:

int(0b101) => 5

If you don't need the prefix, it can be done like this, and then adjusted to the desired lenth:

print(bin(a)[2:].zfill(8))

which results in : 00000101

Answer 2

how to do this with a lambda expression:

to_bin = lambda num: to_bin(num//2) + str(num%2) if num else ""

Answer 3

I find no reason to use a lambda here:

a, b = int(input()), 0
while a > 0:
b.insert(0, a % 2)
a // 2
print(b)

But if you really want it in your code, you can do it like this:
(lambda x: x % 2) (a)

I only use them with map/filter and functions.

Answer 4

Jan Markus you are Genius sir! 🎉🎉 😉
you made my day!

can we do this..
can't we convert that function(i shown in my attempt) into lambda
expression??🤔
not a problem if "no" because your code is impressing.. 🎊
I am fell in love with "f-strings" ❤️

Answer 5

Jan Markus I didn't know thay f strings could do this job so easily. Thanks.