How to find the first repeated consecutive charater in string ?

Question

Can we find it using regex ?
If possible please tell regex pattern
Example :
'**:=1234561123' -> 1
'___commit___' -> m
'1aabv2345568' -> a

Answer 1

In a regex pattern, whatever you put inside () will be a group. Also, you can match the xth group in a pattern by doing \x. For example, if I want the first and last characer to be the same in a string, I can use the pattern
r"^(.).+\1quot;
The \1 will match only if the character is the same as the character in the 1st group. Similarly, \2 will match the second group. Here is a demonstration

https://code.sololearn.com/c7XVdxNJTkR7/?ref=app

These are all the hints you need to solve your problem

Answer 2

Ankeshwarapu Hitesh sorry, but if I tell you the exact pattern, then I would be solving your problem. I want you to solve your problem yourself. That is why I have given you all the hints as to what you need to solve it. If you didn't understand my explanation, let me know. I will link some sources.

Happy coding!

Answer 3

I got it..🕺🕺
The pattern is

r"([a-zA-Z0-9])\1"

Answer 4

Ankeshwarapu Hitesh correct

Answer 5

XXX
Thank you so much for answering my question..
Can u tell exact pattern for my examples ?