Can anyone explain this

Question

Each coffee option has its own number, starting with 0. Write a program that will take a number from the customer as input from the customer and serve the corresponding coffee type. If the customer enters a number that is out of the accepted range, the program should output "Invalid number". Regardless of coffee option result, the program should output "Have a good day" at the end.

Sample Input
7

Sample Output
Invalid number
Have a good day

I finished the challenge with if and else :

coffee = {1:"Café Latte", 2:"Caffe Americano", 3:"Espresso",4:"Cappuccino", 5:"Macchiato"}

choice = int(input ())

if choice == 0:
print(coffee [0])
elif choice == 1:
print(coffee [1])
elif choice == 2:
print(coffee [2])
elif choice == 3:
print(coffee [3])
elif choice == 4:
print(coffee [4])
else:
print ("Invalid number")
print("Have a good day")

But what is required is that the solver of the problem asks me to solve it using try, expact and the finally

How can i do it ??

Answer 1

#Try this

coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
print(coffee[choice])

except:
print("Invalid number")

finally:
print("Have a good day")

Answer 2

《 Nicko12 》 Thanks for trying, but your code failed which contains if but the Simba simba code has succeeded

Thank you all for your participation

Answer 3

coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
print(coffee[choice])
"""
If choice > 4 means IndexError therefore
"except" statement will execute
"""
except:
print ("Invalid number")
finally:

print ("Have a good day")

Answer 4

Xluuk
Oh that, that is a comment or a docstring, not part of the code and not executed, that is just an explanation.

Anyway, You're welcome ☺

Answer 5

I try this
coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
#your code goes here
choise > [4]
except:
#and here
print ("invalid number")
finally:
#and finally here
print ("Have a good day")

But it is valid

Answer 6

《 Nicko12 》
Yes i know

The thing that your code was missing was the print

But thanks for your interest and for trying to help

Answer 7

try:
# get the coffee here
except:
# invalid number
finally:
# have a good day

Answer 8

#Please find my solution below and give me your thoughts, Thx :)

try:
coffee_type = int(input())
if 0 <= coffee_type < 5:
print("Your order has registered")
else:
print("Invalid number, please enter a number between 0 - 4")

except:
print("Invalid number, please enter a number, not a character")
finally:
print("Have a good day")

Answer 9

int main(){

int coffee;
cout << "Choose from 1 - 4 Coffee: ";
cin >> coffee;

switch (coffee) {
case 1:
cout << "Mocha";
break;
case 2:
cout << "Arabica";
break;
case 3:
cout << "Latte";
break;
case 4:
cout << "Espresso";
break;
default:
cout << "Invalid Output";
}

cout << "\nHave a Good Day" << endl;

return 0;

Answer 10

Hope you understand my text!
#include <iostream>
using namespace std;

int main()
{
int num;
cin >> num;
switch (num)
{case 1: cout << "Arabica"<< endl;
cout << "Have a nice day" << endl;
break;
case 2: cout << "Black coffee"<< endl;
cout << "Have a nice day" << endl;
break;
case 3: cout << "Robusta"<< endl;
cout << "Have a nice day" << endl;
break;
case 4: cout << "Latte" << endl;
cout << "Have a nice day" << endl;
break;}
if (num>4){cout << "Invalid" << endl;
cout << "Have a nice day" << endl;}

}