Please give me a error solution in this program.

Question

#include<stdio.h>
#include<string.h>
#include<math.h>
int main()
{
char getbtd[]="1101.1010";
int length,dc=0,i=0,p1=0,p2=-1;
float sum=0;
length=strlen(getbtd);
while(1)
{
if(getbtd[i]=='.')
break;
else
dc++;
i++;
}
for(i=dc-1;i>=0;i++)
{
sum = sum+((int)(getbtd[i]-'0')*pow(2,p1));
p1++;
}
for(i=dc+1;i<length;i++)
{
sum=sum+((int)(getbtd[i]-'0')*pow(2,p2));
p2--;
}
printf("Decimal No is:%f",sum);
return 0;
}

Answer 1

First of all the semicolon after
return 0;
Then second your for loop do not end.

Answer 2

Replace <studio.h> with <stdio.h>

What is the code supposed to do? can you describe that?

(Edit)
Snippet modified.

Answer 3

This loop should be:
for(i=dc-1;i>=0;i--)
{
sum = sum+((int)(getbtd[i]-'0')*pow(2,p1));
p1++;
}
and the solution can be seen as follows:

https://code.sololearn.com/cgIKDXzntAl9/?ref=app

Answer 4

Missing- semicolon after return 0;
Loop do not end.

Answer 5

Replace <studio.h> with <stdio.h>

What is the code supposed to do? can you describe that?

To convert binary to decimal

Answer 6

Yash,
Do you have to do this manually? cause if not, you can use `strtol` function from <stdlib.h>

https://en.cppreference.com/w/cpp/string/byte/strtol