Leap Year practice problem in new Python Beginners course

Question

I feel like the question is written incorrectly and the whole thing doesn’t make any sense really. Can someone else take a look and tell me if I’m tripping and if so explain how it works. It seems like it should be easier I’ve already done 2/3 of Python Core so I figure that should be easy

Answer 1

kole roper

Try this

leapyear = False

year = int(input())

if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
leapyear = True
else:
leapyear = True

if leapyear:
print ("Leap Year")
else:
print ("Not a leap year")

Answer 2

I have figured it out but thanks for the help. i’m sure the answers will help future people

Answer 3

Pls someone help paste the leap question here.

Answer 4

Hunter Allen

There is nothing wrong in that problem. You need to understand again.

You have to apply nested if condition to solve problem.

Answer 5

Ok i will try again thank you

Answer 6

year = int(input())
if year % 4:
else:
print("Not a leap usae")
if year % 100:
else:
print("Leap year")
if year % 400:
print("Leap year")
else:
print("Not a leap year")

icant figure out what im doing wrong

Answer 7

thats what i have

Answer 8

please help

Answer 9

You need to read it again and try this code..
year=int(input())
if year%100==0:
if year%400==0:
print("Leap year")
else:
print("Not a leap year")
else:
if year%4==0:
print("Leap year")
else:
print("Not a leap year")

Answer 10

Just figured it out. Don't need to put the % 100 == 0.
year = int(input())
#your code goes here
if year % 4 == 0 and year % 100 != 0:
print("Leap year")
elif year % 400 == 0:
print("Leap year")
elif year % 400 != 0:
print("Not a leap year")
else:
print("Not a leap year")